The ammonia evolved from the treatment of `0.30g` of an organic compound for the estimation of nitrogen was passed in `100ml` of `0.1 M H_(2)SO_(4)`. The excess acid required `20ml` of `0.5M NaOH` solution for complete neutralisation . The organic compound is:

Options

A. Thiourea
B. Benzamide
C. Urea
D. Acetamide

Answer

C

Explanation

Volume of unsed acid,
`underset("acid")(N_(1)V_(1))=underset("base")(N_(2)V_(2))`
`0.2xxV_(1)=0.5xx20`
`V_(1)=(0.5xx20)/(0.2)=50mL`
Volume of `H_(2)SO_(4)` used `=100-50=50mL`
`%` of `N` in the compound `=(1.4xxVxxN)/(W)`
`=(1.4xx50xx0.2)/(0.30)=46.6%`
The percentage of N is same as in urea `(NH_(2)CONH_(2))`
Percentage of `N=("Mass of "N)/("Mass of urea")xx100`
`=(14xx2)/(60)xx100=46.6%`