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If a^(2) + 16a + k is a perfect square ,...

If `a^(2) + 16a + k` is a perfect square , then find the value of k .

A

4

B

16

C

36

D

64

Text Solution

Verified by Experts

The correct Answer is:
D
`a^(2) + 16a + k = (a)^(2) + 2(a) (8) + k` is a perfect square .
`implies k = 8^(2) = 64`
Hence , the correct option is (d) .
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PEARSON IIT JEE FOUNDATION-EXPRESSIONS AND SPECIAL PRODUCTS -Assessment Tests (Test 1)
  1. Factorise a^(3) - 3b^(2) + 3a^(2) - ab^(2) The following steps are i...

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  2. The following steps are involved in finding the value of 10 (1)/(3) xx...

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  3. If a^(2) + 16a + k is a perfect square , then find the value of k .

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  4. If x + (1)/(x) =2 , then x^(2013) - (1)/(x^(2012)) = "".

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  5. (2x - 6y)^(2) - (6y + 8x)^(2) = ""

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  6. The HCF of 64x^(6) y^(4) , 48 x^(4)y^(8) , and 54x^(5)y^(4 is "".

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  7. Factorise 12a^(3) b^(3) - 3ab.

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  8. (a^(5) - a^(3)) div (a^(2) + a) = ""

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  9. If 3x - (1)/(2x) = 3 , then find the value of (36x^(4) + 1)/(4x^(2)).

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  10. Find the square root of 3^(6n^(2)) (36)^(2a) (16)^(b) .

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  11. (x^(4))/(4) + (y^(3))/(3) - (3z^(2))/(5) + (x^(4))/(3) - (3y^(3))/(5) ...

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  12. {:("Column" A ,, "Column" B), (225x^(2) - 625 y^(2) = ,, (a) 25(x-2) (...

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  13. Factorise a^(3) - 3b^(2) + 3a^(2) - ab^(2) The following steps are i...

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    |

  14. The following steps are involved in finding the value of 10 (1)/(3) xx...

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    |

  15. If a^(2) + 16a + k is a perfect square , then find the value of k .

    Text Solution

    |

  16. If x + (1)/(x) =2 , then x^(2013) - (1)/(x^(2012)) = "".

    Text Solution

    |

  17. (2x - 6y)^(2) - (6y + 8x)^(2) = ""

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    |

  18. The HCF of 64x^(6) y^(4) , 48 x^(4)y^(8) , and 54x^(5)y^(4 is "".

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  19. Factorise 12a^(3) b^(3) - 3ab.

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  20. (a^(5) - a^(3)) div (a^(2) + a) = ""

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