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A radiation of wavelength 300 nm is inci...

A radiation of wavelength 300 nm is incident on a silver surface. Will photoelectrons be observed ?

Text Solution

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Energy of the incidet photon is
`E = h upsilon = (hc)/(lambda)` (in joules)
`E = (hc)/(lambda e)` (in eV)
Substituting the known values, we get
`E = (6.626 xx 10^(-34) xx 3 xx 10^(8))/(300 xx 10^(-9) xx 1.6 xx 10^(-19))`
E = 4.14 eV
the work function of silver = 4.7 eV. Since the energy of the incident photon is less than the work function of silver, photoelectrons are not observed in this case.
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