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A light of wavelength 500 nm is incident...

A light of wavelength 500 nm is incident on a sensitive plate of photoelectric work function 1.235 eV. The kinetic energy of the photo electrons emitted is be (Take h = `6.6 xx 10^(-34)` Js)

A

0.58 eV

B

2.48 eV

C

1.24 eV

D

1.16 eV

Text Solution

Verified by Experts

The correct Answer is:
C

`KE_(max) = (hc)/(lambda) - phi`
`= ((6.6 xx 10^(-34) xx 3 xx 10^(8))/(500 xx 10^(-9) xx 1.6 xx 10^(-19))) - 1.235`
= (2.48 - 1.235)eV = 1.245 eV
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