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An AC voltage with peak value 20 V is c...

An AC voltage with peak value 20 V is connected in series a diode and load resistance of 500 `omega` exists across the diode calculate the peak current through the diode and peak voltage across the load resistance what will be the answer if the diode is ideal

Text Solution

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the diode will conduct during half cycle when it is forward biased Let `V_(B)` be the parrier potential resistance of the diode and load respectively
`V_(0) ` be the peak voltage applied
Effective potential difference across the circuit = `V_(0) - V_(B)`
For ideal diode `R_(D) = 0 rArr V_(B) = 0`
`i_(0) = (V_(0))/( R_(L)) = (20)/( 500) = 0.04 A`
Since there is no resistance offered by the diode when across the load resisitance only
`V_(B) = V_(0) = 20 V`
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