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The escape velocity for a body projected...

The escape velocity for a body projected from a planet depends on

A

mass of the body

B

angle of projection

C

mass of the planet

D

radius of the body

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To determine what the escape velocity for a body projected from a planet depends on, we can derive the formula for escape velocity and analyze its components. Here’s a step-by-step solution: ### Step 1: Understand Escape Velocity Escape velocity is the minimum velocity required for an object to break free from the gravitational attraction of a planet without any further propulsion. ### Step 2: Gravitational Potential Energy The gravitational potential energy (U) of an object of mass \( m \) at a distance \( r \) from the center of a planet of mass \( M \) is given by the formula: \[ U = -\frac{GMm}{r} \] where \( G \) is the gravitational constant. ### Step 3: Kinetic Energy The kinetic energy (K.E) of the object when it is projected with an initial velocity \( v_e \) (escape velocity) is given by: \[ K.E = \frac{1}{2}mv_e^2 \] ### Step 4: Setting Up the Energy Conservation Equation For the object to escape the gravitational field, the kinetic energy must be equal to the magnitude of the gravitational potential energy: \[ \frac{1}{2}mv_e^2 = \frac{GMm}{r} \] ### Step 5: Canceling Mass Since the mass \( m \) of the object appears on both sides of the equation, we can cancel it out: \[ \frac{1}{2}v_e^2 = \frac{GM}{r} \] ### Step 6: Solving for Escape Velocity Now, we can solve for \( v_e \): \[ v_e^2 = \frac{2GM}{r} \] Taking the square root of both sides gives us the formula for escape velocity: \[ v_e = \sqrt{\frac{2GM}{r}} \] ### Step 7: Analyzing the Dependencies From the derived formula, we can see that: - Escape velocity \( v_e \) depends on the mass of the planet \( M \). - Escape velocity \( v_e \) depends on the radius of the planet \( r \). - Escape velocity does **not** depend on the mass of the object \( m \) or the angle of projection. ### Conclusion The escape velocity for a body projected from a planet depends on the mass of the planet and the radius of the planet.
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