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The length of one rod l(1)=3.323cm and t...

The length of one rod `l_(1)=3.323cm` and the other is `l_(2)=3.321cm` both rods were measured with one measuring instrument with least count 0.001 cm Then`(l_(1)-l_(2))` is

A

`(0,002 pm 0.001)cm`

B

`(0.002 pm 0.000)cm`

C

`(0.002 pm 0.002)cm`

D

None of these

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The correct Answer is:
To solve the problem of finding \( l_1 - l_2 \) given the lengths of two rods and their uncertainties, we will follow these steps: 1. **Identify the lengths and uncertainties**: - The length of the first rod \( l_1 = 3.323 \, \text{cm} \) with an uncertainty of \( \Delta l_1 = 0.001 \, \text{cm} \). - The length of the second rod \( l_2 = 3.321 \, \text{cm} \) with an uncertainty of \( \Delta l_2 = 0.001 \, \text{cm} \). 2. **Calculate the difference in lengths**: \[ l_1 - l_2 = 3.323 \, \text{cm} - 3.321 \, \text{cm} = 0.002 \, \text{cm} \] 3. **Determine the uncertainty in the difference**: - When subtracting two measurements, the uncertainties add up. Therefore, the total uncertainty \( \Delta (l_1 - l_2) \) is given by: \[ \Delta (l_1 - l_2) = \Delta l_1 + \Delta l_2 = 0.001 \, \text{cm} + 0.001 \, \text{cm} = 0.002 \, \text{cm} \] 4. **Combine the results**: - The result for \( l_1 - l_2 \) with its uncertainty is: \[ l_1 - l_2 = 0.002 \, \text{cm} \pm 0.002 \, \text{cm} \] 5. **Final result**: - Thus, the final answer is: \[ l_1 - l_2 = 0.002 \, \text{cm} \pm 0.002 \, \text{cm} \]

To solve the problem of finding \( l_1 - l_2 \) given the lengths of two rods and their uncertainties, we will follow these steps: 1. **Identify the lengths and uncertainties**: - The length of the first rod \( l_1 = 3.323 \, \text{cm} \) with an uncertainty of \( \Delta l_1 = 0.001 \, \text{cm} \). - The length of the second rod \( l_2 = 3.321 \, \text{cm} \) with an uncertainty of \( \Delta l_2 = 0.001 \, \text{cm} \). 2. **Calculate the difference in lengths**: \[ ...
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DISHA PUBLICATION-PHYSICAL WORLD, UNITS AND MEASUREMENTS-Exercise - 1 : Concept Builder (Topicwise)(Topic 2 : Errors in Measurements and Significant Figures)
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  2. A vernier callipers has its main scale 10 cm equally divided into 250 ...

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  3. The length of one rod l(1)=3.323cm and the other is l(2)=3.321cm both ...

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  4. The relative density of material of a body is found by weighting it fi...

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  5. A physical quantity X is represented by X = (M^(x) L^(-y) T^(-z). The ...

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  6. Percentage error in the measurement of mass and speed are 2% and 3% re...

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  7. The least count of a stop watch is (1//5)s. The time 20 oscillations o...

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  8. The internal and external diameters of a hollow cylinder are measured ...

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  9. The diameter of a sphere is measured with the instrument having least ...

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  10. In a vernier callipers, ten smallest divisions of the vernier scale ar...

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  11. A physical quantity is given by X=M^(a)L^(b)T^(c). The percentage erro...

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  12. In a simple pendulum experiment for the determination of acceleration ...

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  13. The relative error in the dertmination of the surface area of a spher...

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  14. The density of a cube is measured by measuring its mass and length of ...

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  15. A student measured the diameter of a wire using a screw gauge with lea...

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  16. In a vernier callipers, N divisions of vernier scale coincide with (N-...

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  17. A screw gauge has 200 equal divisions marked along the circumference o...

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  18. The refractive index of water measured by the relation m = (real \ dep...

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  19. N divisions on the main scale of a vernier callipers coincide with (N+...

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  20. A wire has a mass (0.3pm0.003) g, radius (0.5pm0.005) mm and length (6...

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