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A particle moves from the point (2.0hati...

A particle moves from the point `(2.0hati+4.0hatj)`m at t=0, with an initial velocity (`5.0hati+4.0hatj)ms^(-1)`. It is acted upon by constant acceleration `(4.0hati+4.0hatj)ms^(-2)`. What is the distance (im metre) of the particle from the origin at time 2s?

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To solve the problem step by step, we will use the equations of motion under constant acceleration. ### Step 1: Identify the initial conditions - Initial position \( \mathbf{r_0} = 2.0 \hat{i} + 4.0 \hat{j} \) m - Initial velocity \( \mathbf{u} = 5.0 \hat{i} + 4.0 \hat{j} \) m/s - Constant acceleration \( \mathbf{a} = 4.0 \hat{i} + 4.0 \hat{j} \) m/s² - Time \( t = 2 \) s ...
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