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The position vector of a partcle vecr(t)...

The position vector of a partcle `vecr(t)=15t^(2)hati+(4-20t^(2))hatj`. What is the magnitude of the acceleration (in `m//s^(2)`) at t=1?

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To find the magnitude of the acceleration of the particle at \( t = 1 \), we will follow these steps: ### Step 1: Write down the position vector The position vector of the particle is given as: \[ \vec{r}(t) = 15t^2 \hat{i} + (4 - 20t^2) \hat{j} \] ...
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