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A body is thrown horizontally from the top of a tower of height 5m. It touches the ground at a distance of 10 m from the foot of the tower. The initial velcotiy (in m/s) of the body is `(g=10ms^(-2)`)

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To solve the problem, we need to find the initial velocity \( u \) of a body thrown horizontally from the top of a tower of height \( h = 5 \) m, which lands at a horizontal distance \( R = 10 \) m from the foot of the tower. We will use the equations of motion for both vertical and horizontal motions. ### Step 1: Calculate the time of flight The time \( t \) it takes for the body to fall from the height of the tower can be calculated using the formula for free fall: \[ h = \frac{1}{2} g t^2 \] ...
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