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int(1)^(2)(e^(1//x))/(x^(2))dx...

`int_(1)^(2)(e^(1//x))/(x^(2))dx`

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Putting `(1)/(x)=t`, we get `I=-int_(1)^(1//2)e^(t)dt=int_(1//2)^(1)e^(t)dt=[e^(t)]_(1//2)^(1)`.
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