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int(0)^(pi//2)(cosx)/((sinx+cosx))dx=(pi...

`int_(0)^(pi//2)(cosx)/((sinx+cosx))dx=(pi)/(4)`

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int_(0)^(pi//2)(sinx)/((sinx+cosx))dx=?

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Knowledge Check

  • int_(0)^((pi)/2)(cos^(3)x)/(sinx+cosx)dx

    A
    `(pi-1)/2`
    B
    `(pi-1)/4`
    C
    `(1+pi)/4`
    D
    `(pi-3)/4`
  • int_(0)^((pi)/2)(cos2x)/(cosx+sinx)dx=

    A
    `-1`
    B
    1
    C
    0
    D
    2
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