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int(0)^(pi//4)(tan^(3)x)/((1+cos2x))dx...

`int_(0)^(pi//4)(tan^(3)x)/((1+cos2x))dx`

Text Solution

Verified by Experts

Using `cos2x=(2cos^(2)x-1)`, we get `I=int_(0)^(pi//4)tan^(3)xsec^(2)xdx`. Now, put `tanx=t`.
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