The decay constant of a radioactive sample is `'lambda'`. The half-life and mean life of the sample are respectively a)`1/lamda,("in"2)/lamda` b)`("in"2)/lamda,1/lamda` c)`"in"2,1/lamda` d)`lamda/("in"2),1/lamda`

Options

A. `(1)/(lamda), (ln 2)/(lamda)`
B. `(ln 2)/(lamda), (1)/(lamda)`
C. `lamda ln 2, (1)/(lamda)`
D. `(lamda)/(ln 2), (1)/(lamda)`

Answer

B

Explanation

`t_(1//2) = (log_(e)2)/(lamda)`, Average life `= (1)/(lamda)`