In the nuclear reaction U92^238 to Pb82^...

In the nuclear reaction `U_92^238 to Pb_82^206`, the number of alpha and beta particles decayed are:

`4 alpha, 3 beta`

`8 alpha, 6 beta`

`6 alpha, 4 beta`

`7 alpha, 5 beta`

Text Solution

Verified by Experts

The correct Answer is:

Number of `alpha`- particles `= (238 - 206)/(4) = 8`
Number of `beta`- particles `= 2xx 8 - 92 + 82 = 6`

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