(cos 4x sin 3x -cos 2x sin x )/(sin 4x ...

`(cos 4x sin 3x -cos 2x sin x )/(sin 4x sin x+ cos 6x cos x)= tan 2x`

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To solve the equation \[ \frac{\cos 4x \sin 3x - \cos 2x \sin x}{\sin 4x \sin x + \cos 6x \cos x} = \tan 2x \] we will simplify the left-hand side and show that it equals the right-hand side. ...

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RS AGGARWAL-TRIGONOMETRIC , OR CIRCULAR, FUNCTIONS-Exercise (15C)

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