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Let vecV=2hati+hatj-hatk and vecW=hati+3...

Let `vecV=2hati+hatj-hatk` and `vecW=hati+3hatk`. It `vecU` is a unit vector, then the maximum value of the scalar triple product `[(vecU, vecV, vecW)]` is

A

`-1`

B

`sqrt(10)+sqrt(6)`

C

`sqrt(59)`

D

`sqrt(60)`

Text Solution

Verified by Experts

The correct Answer is:
C

We have
`[(vecU, vecV, vecW)]=vecU.(vecVxxvecW)`
`implies[(vecU, vecV, vecW)]le|vecU||vecVxxvecW| [ :' veca. vecb le |veca||vecb|]`
`implies[(vecU, vecV, vecW)]le|vecVxxvecW| [ :' |vecU|=1]`
Now,
`vecVxxvecW=|(hati, hatj, hatk),(2,1,-1),(1,0,3)|=3hati-7hatj-hatk`
`:.|vecVxxvecW|=sqrt(9+49+1)=sqrt(59)`
Hence `[(vecU, vecV, vecW)]le sqrt(59)`
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