Two cells of emfs `epsilon_(1)and epsilon_(2)` and internal resistances `r_(1)and r_(2)` respectively are connected in parallel . Obtain expressions for the equivalent (i) resistance and , (ii) emf of the combination.

Explanation

(i) The slope of the graph will given the internal resistance of the cell.
(ii) Expression for emf single equivalent cell. `E= (((E_(1))/(r_(1)) + (E_(2))/(r_(2))))/(((1)/(r_(1)) + (1)/(r_(2)))`
Internal resistance of equivalent cell
`r= (r_(1) xx r_(2))/(r_(1) + r_(2))`