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Mixture X= 0.02 mole of [Co(NH(3))(5) SO...

Mixture X= 0.02 mole of `[Co(NH_(3))_(5) SO_(4)]Br` and 0.02 mol of `[Co(NH_(3))_(5)Br]SO_(4)` was prepared in 2 litre of solution.
1 litre of mixture X + excess `AgNO_(3) to Y`
1 litre of mixture X + excess of `BaCl_(2) to Z`
Number of moles of Y and Z are

A

0.01, 0.01

B

0.02, 0.01

C

0.01, 0.02

D

0.02, 0.02

Text Solution

Verified by Experts

The correct Answer is:
A
Mixture X will contain 0.02 mol `Br^(-)` ions and 0.02 mol `SO_(4)^(2-)` iojns in 2 L solution. Hence 1 L of mixture X will contain 0.01 mol `Br^(-)` and 0.01 mol `SO_(4)^(2-)` ions. With excess of `AgNO_(3)` , 0.01 mol of AgBr i.e. Y is formed. With excess of `BaCl_(2)` , 0.01 mol of `BaSO_(4)` i.e. Z is formed.
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