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The percentage of Se in peroxidase enzym...

The percentage of Se in peroxidase enzyme is 0.5% by weight (atomic weight = 78.4). Then minimum molecular weight of peroxidase anhydrous enzyme is

A

`1.568 xx 10^(4)`

B

`1.568 xx 10^(3)`

C

`15.68`

D

`3.136 xx 10^(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
0.5% by weight means 0.5 g Se is present in 100 g of peroxidase anhydrous enzyme. As at least one atom of Se must be present in the enzyme and atomic weight of Se = 78.4, therefore, 1 g atom of Se i.e. 78.4 g will be present in:
`=100/0.5 xx 78.4 = 1.568 xx 10^(4)` g in enzyme.
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