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If A^(2) - A + I = 0 , then the inverse...

If `A^(2) - A + I = 0 ` , then the inverse of the matrix A is

A

A - I

B

I - A

C

A+ I

D

A

Text Solution

AI Generated Solution

The correct Answer is:
To find the inverse of the matrix \( A \) given the equation \( A^2 - A + I = 0 \), we can follow these steps: ### Step 1: Rearranging the Equation Start with the given equation: \[ A^2 - A + I = 0 \] Rearranging this, we get: \[ A^2 - A = -I \] ### Step 2: Factoring the Left Side We can factor the left side: \[ A(A - I) = -I \] ### Step 3: Multiplying by the Inverse To isolate \( A \), we can multiply both sides by \( A^{-1} \) (assuming \( A \) is invertible): \[ A^{-1} A(A - I) = A^{-1}(-I) \] This simplifies to: \[ A - I = -A^{-1} \] ### Step 4: Rearranging for \( A^{-1} \) Now, rearranging gives us: \[ A^{-1} = I - A \] ### Conclusion Thus, the inverse of the matrix \( A \) is: \[ A^{-1} = I - A \]
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