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x^2+2sqrt(3)x-24...

`x^2+2sqrt(3)x-24`

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To factor the polynomial \( x^2 + 2\sqrt{3}x - 24 \), we will follow these steps: ### Step 1: Identify the coefficients The polynomial can be expressed in the standard form \( ax^2 + bx + c \), where: - \( a = 1 \) - \( b = 2\sqrt{3} \) - \( c = -24 \) ### Step 2: Calculate the product \( ac \) We need to calculate \( ac \): \[ ac = 1 \times (-24) = -24 \] ### Step 3: Find two numbers that multiply to \( ac \) and add to \( b \) We need to find two numbers \( m \) and \( n \) such that: - \( m \cdot n = -24 \) - \( m + n = 2\sqrt{3} \) After testing various pairs of factors of \(-24\), we find: - \( m = 4\sqrt{3} \) - \( n = -2\sqrt{3} \) ### Step 4: Rewrite the middle term using \( m \) and \( n \) We can rewrite the polynomial by splitting the middle term: \[ x^2 + 4\sqrt{3}x - 2\sqrt{3}x - 24 \] ### Step 5: Group the terms Now, we group the terms: \[ (x^2 + 4\sqrt{3}x) + (-2\sqrt{3}x - 24) \] ### Step 6: Factor by grouping Now, we factor out the common factors from each group: 1. From the first group \( x^2 + 4\sqrt{3}x \): \[ x(x + 4\sqrt{3}) \] 2. From the second group \( -2\sqrt{3}x - 24 \): \[ -2\sqrt{3}(x + 4\sqrt{3}) \] Now, we can combine these: \[ x(x + 4\sqrt{3}) - 2\sqrt{3}(x + 4\sqrt{3}) \] ### Step 7: Factor out the common binomial Now we can factor out the common binomial \( (x + 4\sqrt{3}) \): \[ (x + 4\sqrt{3})(x - 2\sqrt{3}) \] ### Final Answer Thus, the factored form of the polynomial \( x^2 + 2\sqrt{3}x - 24 \) is: \[ (x + 4\sqrt{3})(x - 2\sqrt{3}) \] ---

To factor the polynomial \( x^2 + 2\sqrt{3}x - 24 \), we will follow these steps: ### Step 1: Identify the coefficients The polynomial can be expressed in the standard form \( ax^2 + bx + c \), where: - \( a = 1 \) - \( b = 2\sqrt{3} \) - \( c = -24 \) ...
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