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x^2-32x-105...

`x^2-32x-105`

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To factor the quadratic polynomial \( x^2 - 32x - 105 \), we can use the method of middle term splitting. Here’s a step-by-step solution: ### Step 1: Identify the coefficients The given polynomial is in the form \( ax^2 + bx + c \), where: - \( a = 1 \) - \( b = -32 \) - \( c = -105 \) ### Step 2: Find the product and sum We need to find two numbers that: - Multiply to \( ac = 1 \times (-105) = -105 \) - Add up to \( b = -32 \) ### Step 3: List the factor pairs of -105 The factor pairs of -105 are: - \( 1 \) and \( -105 \) - \( -1 \) and \( 105 \) - \( 3 \) and \( -35 \) - \( -3 \) and \( 35 \) - \( 5 \) and \( -21 \) - \( -5 \) and \( 21 \) - \( 7 \) and \( -15 \) - \( -7 \) and \( 15 \) ### Step 4: Identify the correct pair From the factor pairs, we need to find a pair that adds up to -32. The correct pair is: - \( -35 \) and \( 3 \) because \( -35 + 3 = -32 \) ### Step 5: Rewrite the middle term We can rewrite the polynomial using the numbers we found: \[ x^2 - 35x + 3x - 105 \] ### Step 6: Group the terms Now, we group the terms: \[ (x^2 - 35x) + (3x - 105) \] ### Step 7: Factor by grouping Now, we factor out the common factors from each group: \[ x(x - 35) + 3(x - 35) \] ### Step 8: Factor out the common binomial Now, we can factor out the common binomial \( (x - 35) \): \[ (x - 35)(x + 3) \] ### Final Answer Thus, the factorization of the polynomial \( x^2 - 32x - 105 \) is: \[ (x - 35)(x + 3) \]
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