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If P=[[sqrt(3)/2,1/2],[-1/2,sqrt(3)/2]],...

If `P=[[sqrt(3)/2,1/2],[-1/2,sqrt(3)/2]], A=[[1,1],[0,1]]` and `Q=PAP^T`, then `P^TQ^(2015)P` is

A

`[(0,2015),(0,0)]`

B

`[(2015,0),(1,2015)]`

C

`[(1,2015),(0,1)]`

D

`[(2015,1),(0,2015)]`

Text Solution

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The correct Answer is:
C
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