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All the following complex ions are found...

All the following complex ions are found to be paramagnetic
`P=[FeF_(6)]^(3-)` `Q=[CoF_(6)]^(3-)` `R=[V(H_(2)O)_(6)]^(3+)` `S=[T:(H_(2)O)_(6)]^(3+)`
The correct order of their paramagnetic moment (spin only) is

A

`PgtQgtRgtS`

B

`PltQltRltS`

C

P=Q=R=S

D

`PgtRgtQgtS`

Text Solution

Verified by Experts

The correct Answer is:
A

Both F and `H_(2)O` are weak field ligands. So no regrouping of electrons occurs. Hence the unpaired electrons will be left as such (5, 4, 2, 1)
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