`D(+)` Glucose has melting point `140^(@)C` and specific rotation `[a]_(D)^(25)` is `112^(@)C`. Another D(+) Glucose has melting point `150^(@)C` and specific rotation `[a]_(D)^(25)` is `+18.7^(@)C`. The two form have significantly different optical rotation but when an aqueous solution of either form is allowed to stand, it rotation changes. The specific rotation of one form decreases and rotation of other increases until both solution show the same value `+52.7^(@)`. The change in rotation towards an equilibrium value is called mutarotation

`[alpha]_(D)^(25) = +18.7^(@)C " " [alpha]_(D)^(25) = +112^(@)C`
Mutarotation is characteristic feature of

Options

A. Epimer
B. Enantiomer
C. Anomer
D. Ring chain isomer

Answer

C

Explanation

Mutarotation