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I=int \ loge (logex)/(x(loge x))dx...

`I=int \ log_e (log_ex)/(x(log_e x))dx`

Text Solution

Verified by Experts

The correct Answer is:
`((log_(e)(log_(e)x))^(2))/(2)+C`
`intlog_(e)(log_(e)x)*(1)/(x log_(e)x)dx`
`=int log_(e)(log_(e)x)*(log_(e)(log_(e)x))'dx`
`=((log_(e)(log_(e)x))^(2))/(2)+C`
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