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The area of a regular polygon of n sides...

The area of a regular polygon of `n` sides is (where `r` is inradius, `R` is circumradius, and `a` is side of the triangle) `(n R^2)/2sin((2pi)/n)` (b) `n r^2tan(pi/n)` `(n a^2)/4cotpi/n` (d) `n R^2tan(pi/n)`

A

`(nR^(2))/(2) sin ((2pi)/(n))`

B

`nr^(2) tan ((pi)/(n))`

C

`(na^(2))/(4) cot.(pi)/(n)`

D

`nR^(2) tan((pi)/(n))`

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The correct Answer is:
To solve the problem, we need to determine the area of a regular polygon with \( n \) sides in terms of its inradius \( r \), circumradius \( R \), and side length \( a \). The options provided are: 1. \( \frac{n R^2}{2 \sin\left(\frac{2\pi}{n}\right)} \) 2. \( n r^2 \tan\left(\frac{\pi}{n}\right) \) 3. \( \frac{n a^2}{4 \cot\left(\frac{\pi}{n}\right)} \) 4. \( n R^2 \tan\left(\frac{\pi}{n}\right) \) ### Step-by-Step Solution: **Step 1: Understand the relationship between the inradius, circumradius, and side length.** For a regular polygon: - The side length \( a \) can be expressed in terms of the circumradius \( R \) as: \[ a = 2R \sin\left(\frac{\pi}{n}\right) \] **Hint:** Remember that the circumradius \( R \) relates to the side length \( a \) through the sine function. --- **Step 2: Calculate the area of the polygon using the side length.** The area \( A \) of a regular polygon can be calculated using the formula: \[ A = \frac{n a^2}{4 \tan\left(\frac{\pi}{n}\right)} \] **Hint:** The area formula for a polygon is based on the number of sides and the square of the side length. --- **Step 3: Substitute the expression for \( a \) into the area formula.** Substituting \( a = 2R \sin\left(\frac{\pi}{n}\right) \) into the area formula: \[ A = \frac{n (2R \sin\left(\frac{\pi}{n}\right))^2}{4 \tan\left(\frac{\pi}{n}\right)} = \frac{n \cdot 4R^2 \sin^2\left(\frac{\pi}{n}\right)}{4 \tan\left(\frac{\pi}{n}\right)} = n R^2 \frac{\sin^2\left(\frac{\pi}{n}\right)}{\tan\left(\frac{\pi}{n}\right)} \] **Hint:** When substituting, make sure to simplify the expression correctly. --- **Step 4: Use the identity \( \tan(x) = \frac{\sin(x)}{\cos(x)} \) to simplify further.** Using the identity for tangent: \[ A = n R^2 \frac{\sin^2\left(\frac{\pi}{n}\right)}{\frac{\sin\left(\frac{\pi}{n}\right)}{\cos\left(\frac{\pi}{n}\right)}} = n R^2 \sin\left(\frac{\pi}{n}\right) \cos\left(\frac{\pi}{n}\right) \] **Hint:** Remember to apply trigonometric identities to simplify expressions. --- **Step 5: Relate the area to the inradius \( r \).** The area can also be expressed in terms of the inradius \( r \): \[ A = \frac{n r^2}{\tan\left(\frac{\pi}{n}\right)} \] **Hint:** This relationship shows how the area can be expressed using the inradius. --- **Step 6: Conclusion and answer selection.** From our calculations, we have derived two valid expressions for the area of a regular polygon: 1. \( A = n R^2 \tan\left(\frac{\pi}{n}\right) \) 2. \( A = n r^2 \tan\left(\frac{\pi}{n}\right) \) Thus, the correct options are: - \( n r^2 \tan\left(\frac{\pi}{n}\right) \) (Option b) - \( n R^2 \tan\left(\frac{\pi}{n}\right) \) (Option d) **Final Answer:** Options (b) and (d) are correct. ---

To solve the problem, we need to determine the area of a regular polygon with \( n \) sides in terms of its inradius \( r \), circumradius \( R \), and side length \( a \). The options provided are: 1. \( \frac{n R^2}{2 \sin\left(\frac{2\pi}{n}\right)} \) 2. \( n r^2 \tan\left(\frac{\pi}{n}\right) \) 3. \( \frac{n a^2}{4 \cot\left(\frac{\pi}{n}\right)} \) 4. \( n R^2 \tan\left(\frac{\pi}{n}\right) \) ### Step-by-Step Solution: ...
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