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Which of the following function/function...

Which of the following function/functions is/are periodic ?
(a) `sgn(e^(-x)) " (b) " sinx + |sinx|`
(c ) `min(sinx, |x|) " (d) " (x)/(x)`

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To determine which of the given functions is periodic, we will analyze each option step by step. ### Step 1: Analyze Option (a) \( \text{sgn}(e^{-x}) \) The function \( \text{sgn}(e^{-x}) \) is defined as follows: - \( \text{sgn}(y) = 1 \) if \( y > 0 \) - \( \text{sgn}(y) = 0 \) if \( y = 0 \) - \( \text{sgn}(y) = -1 \) if \( y < 0 \) Since \( e^{-x} \) is always positive for all real \( x \), we have: \[ \text{sgn}(e^{-x}) = 1 \text{ for all } x \] This means the function is constant and does not repeat values over any interval. Therefore, it is not periodic. ### Conclusion for (a): **Not periodic.** --- ### Step 2: Analyze Option (b) \( \sin x + |\sin x| \) The function can be rewritten as: - If \( \sin x \geq 0 \), then \( |\sin x| = \sin x \) and \( f(x) = \sin x + \sin x = 2\sin x \) - If \( \sin x < 0 \), then \( |\sin x| = -\sin x \) and \( f(x) = \sin x - \sin x = 0 \) The function is periodic because: - \( 2\sin x \) is periodic with period \( 2\pi \) - The constant function \( 0 \) is also periodic. Thus, the overall function \( f(x) \) retains periodicity. ### Conclusion for (b): **Periodic with period \( 2\pi \).** --- ### Step 3: Analyze Option (c) \( \min(\sin x, |x|) \) To analyze this function, we need to consider the behavior of both \( \sin x \) and \( |x| \): - \( \sin x \) is periodic with period \( 2\pi \). - \( |x| \) is not periodic; it increases indefinitely as \( x \) moves away from zero. The minimum function will switch between \( \sin x \) and \( |x| \) depending on the value of \( x \). As \( |x| \) grows larger than \( \sin x \), the function will not repeat its values, leading to a break in periodicity. ### Conclusion for (c): **Not periodic.** --- ### Step 4: Analyze Option (d) \( \frac{x}{x} \) The function \( \frac{x}{x} \) is defined as: - \( 1 \) for \( x \neq 0 \) - Undefined for \( x = 0 \) Since the function takes the constant value \( 1 \) for all \( x \) except at \( x = 0 \), it does not repeat values over any interval. Therefore, it is not periodic. ### Conclusion for (d): **Not periodic.** --- ### Final Summary: - (a) Not periodic - (b) Periodic - (c) Not periodic - (d) Not periodic

To determine which of the given functions is periodic, we will analyze each option step by step. ### Step 1: Analyze Option (a) \( \text{sgn}(e^{-x}) \) The function \( \text{sgn}(e^{-x}) \) is defined as follows: - \( \text{sgn}(y) = 1 \) if \( y > 0 \) - \( \text{sgn}(y) = 0 \) if \( y = 0 \) - \( \text{sgn}(y) = -1 \) if \( y < 0 \) ...
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