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lim(xrarr(pi)/(2)) (1-sinx)tanx=...

`lim_(xrarr(pi)/(2)) (1-sinx)tanx=`

A

`(pi)/(2)`

B

1

C

0

D

`oo`

Text Solution

Verified by Experts

The correct Answer is:
C
`underset(xrarrpi//2)(lim)(1-sinx)tanx`
`" "=underset(xrarrpi//2)(lim)sinx(1-sinx)/(cosx)`
`" "=underset(xrarrpi//2)(lim)((1-sin^(2)x))/(cosx(1+sinx))`
`" "=underset(xrarrpi//2)(lim)(cos^(2)x)/(cosx(1+sinx))`
`" "=underset(xrarrpi//2)(lim)(cosx)/(1+sinx)=0`
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CENGAGE ENGLISH-LIMITS-Single Correct Answer Type
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