Home
Class 11
PHYSICS
A body of mass 0.1 kg is executing SHM a...

A body of mass 0.1 kg is executing SHM according to the equation
`y=0.5 cos (100 t+(3pi)/(4))` metre
Find (i) the frequency of oscillation (ii) initial phase (iii) maximum velocity (iv) maximum acceleration and (v) total energy.

Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    SL ARORA|Exercise Problem|23 Videos

  • OSCILLATIONS

    SL ARORA|Exercise Problems for self practice|67 Videos

  • OSCILLATIONS

    SL ARORA|Exercise Type D Based on Other Examples of SHM|2 Videos

  • MOTION IN ONE DIMENSION

    SL ARORA|Exercise problems for self practice|66 Videos

  • Physical world

    SL ARORA|Exercise Exercise|49 Videos

Similar Questions

Explore conceptually related problems

A body of mass 0.1 kg is executing SHM according to the equation y=0.5cos(100t+(3pi/4) meter. Find the frequency of oscillation.

A body is executing SHM according to the equation : y = 14 sin( 100 pi t + (pi/6)) cm. Find its maximum speed.

A body is executing SHM according to the equation : y = 14 sin( 100 pi t + (pi/6)) cm. Find its maximum acceleration.

A body of mass 1 kg executes SHM which is given by y=6.0 cos (100t+(pi)/(4)) cm What is the (i) amplitude of displacement (ii) frequency (iii) initial phase (iv) velocity (v) acceleration and (vi) maximum kinetic energy ?

A particle executes SHM represented by the equation, y = 0.02 sin (3.14t+(pi)/(2))m . Find (i) amplitude (ii) time period (iii) frequecy (iv) epoch (v) maximum velocity and (vi) maximum acceleration.

A particle executing SHM according to the equation x=5cos(2pit+(pi)/(4)) in SI units. The displacement and acceleration of the particle at t=1.5 s is

The displacement of a particle of mass 100 g executing SHm is given by the equation y = 0.2 cos (100t+(pi)/(4)) meter. Its total energy is

The amplitude of a simple harmonic oscillation is doubled. How does this affect (i) periodic time (ii) maximum velocity (iii) maximum acceleration and (iv) maximum energy

A particle oscillates with S.H.M. according to the equation x = 10 cos ( 2pit + (pi)/(4)) . Its acceleration at t = 1.5 s is

If amplitude of a particle executing SHM is doubled, which of the following quantities are doubled (i) Time period (ii) Maximum velocity (iii) Maximum acceleration (iv) Total energy

SL ARORA-OSCILLATIONS-Example
  1. A body of mass 0.1 kg is executing SHM according to the equation y=0...

    Text Solution

    |

  2. A body of mass 0.1 kg is executing SHM according to the equation y=0...

    Text Solution

    |

  3. A body of mass 0.1 kg is executing SHM according to the equation y=0...

    Text Solution

    |

  4. A block whose mass is 1 kg is fastened to a spring.The spring has a s...

    Text Solution

    |

  5. A body executes SHM of time period 8 s. if its mass be 0.1 kg, its vel...

    Text Solution

    |

  6. A body executes SHM of time period 8 s. if its mass be 0.1 kg, its vel...

    Text Solution

    |

  7. A body executes SHM of time period 8 s. if its mass be 0.1 kg, its vel...

    Text Solution

    |

  8. A spring of force constant 800N//m has an extension of 5cm. The work d...

    Text Solution

    |

  9. A particle of mass 10 g is describing SHM along a straight line with a...

    Text Solution

    |

  10. A particle of mass 10 g is describing SHM along a straight line with a...

    Text Solution

    |

  11. At a time when the displacement is half the amplitude, what fraction o...

    Text Solution

    |

  12. A particle is executing SHM of amplitude A. at what displacement from ...

    Text Solution

    |

  13. A particle executes simple harmonic motion of ampliltude A. At what di...

    Text Solution

    |

  14. A particle executes simple harmonic motion of amplitude A. At what poi...

    Text Solution

    |

  15. Derive ann expression for the time period of a SHM in terms of inertia...

    Text Solution

    |

  16. The pan attached to a spring balance has a mass of 1 kg. A weight of ...

    Text Solution

    |

  17. A spring compressed by 0.2 m develops a restoring force of 25 N. A bod...

    Text Solution

    |

  18. A spring compressed by 0.2 m develops a restoring force of 25 N. A bod...

    Text Solution

    |

  19. A spring compressed by 0.2 m develops a restoring force of 25 N. A bod...

    Text Solution

    |

  20. A 0.2kg of mass hangs at the end of a spring. When 0.02kg more mass is...

    Text Solution

    |