A cylidrical wooden piece of cork floats in a liquid of density `sigma`. The cork is depressed slightly and released. Show that the cork will oscillate up and down simple harmonicaly with a period.
`T=2pisqrt((rhoh)/(sigmag))`, where `rho` is the density of the cork.

A cylindrical piece of cork of base area A and height h floats in a liquid of density rho_(1) . The cork is depressed slightly and then released. Show that the cork oscillates up and down simple harmonically with a period T=2pisqrt((hrho)/(rho_(1)g))

A solid cube of side a and density rho_(0) floats on the surface of a liquid of density rho . If the cube is slightly pushed downward, then it oscillates simple harmonically with a period of

A cylinderical log of wood of height h and area of cross-section A floats in water. It is pressed and then released. Show that the log would execute S.H.M. with a tiem period. T=2pisqrt((m)/(Arhog) where m is mass of the body and rho is density of the liquid.

A solid sphere of radius R is floating in a liquid of density sigma with half of its volume submerged. If the sphere is slightly pushed and released , it starts axecuting simple harmonic motion. Find the frequency of these oscillations.

A cylindrical log of wood of height h and area of cross-section A floats in water. It is pressed and then released. Show that lon would execute SHM with a time period. T=2pisqrt((m)/(Apg)) where, m is mass of the body and p is density of the liquid.

A cylindrical of wood (density = 600 kg m^(-3) ) of base area 30 cm^(2) and height 54 cm , floats in a liquid of density 900 kg^(-3) The block is deapressed slightly and then released. The time period of the resulting oscillations of the block would be equal to that of a simple pendulum of length (nearly) :

A wooden cube (density of wood 'd' ) of side 'l' flotes in a liquid of density 'rho' with its upper and lower surfaces horizonta. If the cube is pushed slightly down and released, it performs simple harmonic motion of period 'T' . Then, 'T' is equal to :-

The system of simple pendulum is immersed in liquid of a density rho_(l) . Prove that its new period of oscillation inside the liquid will be T = 2pi sqrt((l)/(g(1-(rho_(l))/(rho_(s))))) where rho_(s) is density of bob.

A U - tube of uniform cross section contains mercury upto a height h in either limb. The mercury in one limbe is depressed a little and then relased. Obtain an expression for time period (T) of oscillation, assuming that T depends on h, rho and g, where rho is density of mercury.