Time period of a particle in `SHM` depends on the force constant `k` and mass `m` of the particle `T = 2psqrt((m)/(k))`. A simple pendulum exeutes `SHM` approximately. Why then is the period of a pendulum independent of the mass of the pendulum ?

Answer the following questions: (a) Time period of particle is S.H.M. depends on the force constant k and mass m of the particle : T=2pisqrt(m//k). A simple pendulum executes S.H.M. approximately. Why then is the time-period of a pendulum independent of the mass of the pendulum? (b) The motino of simple pendulum is approximatley simple harmonic for small angles of oscillation. For large angle of oscillation, a more involved analysis (beyond the scope of this book) shows that T is greater that 2pisqrt(l//g) . Think of a quanlitative argument to appreciate this result. (c) A man with a wrist watch on his hand falls from the top of tower. Does the watch give correct time during the free fall? (d) What is teh frequency of oscillation of a simple pendulum mounted iin a cabin that is freely falling under gravity?

The time period of a simple pendulum depends on its______

Time period of simple pendulum of wire is independent

The time period of a simple pendulum of length 9.8 m is

The time period of a simple pendulum depends on its _______.

The time period of a simple pendulum is independent of _______ of oscillation.

The length of simple pendulum executing SHM is increased by 21% . By what % time period of pendulum increase ?