When two capacitors `C_1` and `C_2` are in parellel, the equivalent capacitance is `C_(II)`. When the same two are in series the equivalent is `C_(s)` . The ratio of `(C_(II))/(C_(s))` is `15:4` . Find `(C_2)/(C_1)`

Four capacitors of equal capacitance have an equivalent capacitance C_(1) when connected in series and an equivalent capacitance C_(2) when connected in parallel. The ratio (C_(1))/(C_(2)) is

When two capacitors are connected in series, the equivalent capacitance is 1.2muF . When they are connected in parallel, the equivalent capacitance is 5muF . The capacitances of the capacitors are

If each capacitor has capacitance C, then equivalent capacitance between A and B is

Each capacitor has cpacitance C . . The equivalent capacitance between 4 and 5 is .

Consider the combination of 2 capacitors C_1 and C_2 with C_2gtC_1 , when connected in parallel, the equivalent capacitance is 15/4 time the equivalent capacitance of the same connected in series. Calculate the ratio of capacitors, C_2/C_1

If C_(S) and C_(P) are the equivalent capacities of n identical condensers joined in series and in parallel respectively, then the ratio (C_(P))/(C_(S)) is

The effective capacitance of two capacitors of capacitances C_(1) and C_(2)(C_(2)gtC_(1)) connected in parallel is (25)/(6) times the effective capacitance when they are connected in series. The ratio (C_(2))/(C_(1)) is

Condensers of capacity 4muF , 5muF and 6muF are connected first in series . The effective capacitance is C_(1) . When they are connected in parallel, the effective capacitance is C_(2) . Then the ratio C_(2)//C_(1) will be

Consider three capacitors of capacitance C_(1),C_(2) and C_(3) . If C_(1), C_(2) and C_(3) in parallel, the equivalent capacitance is 6 unit, while C_(2) and C_(3) in parallel, the equivalent capacitance is 5 unit. If C_(1).C_(2).C_(3)=6 , then the capacitance are