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Find the force of attraction between a s...

Find the force of attraction between a solid sphere of mass `M` and a ring of mass `m` as shown.

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B, C
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Knowledge Check

  • The gravitational force of attraction between a uniform sphere of mass M and a uniform rod of length l and mass in as shown in figure is

    A
    `(GMm)/(r (r + 1))`
    B
    `(GM)/(r^2)`
    C
    `Mm^2`
    D
    `(r^2 + 1) mM`

  • Find the gravitational force of attraction between the ring and sphere as shown in the diagram, where the plane of the ring is perpendicular to the line joining the centres. If sqrt8R is the distance between the centres of a ring (of mass 'm') and a sphere (mass "M") where both have equal radius "R'

    A
    `sqrt8/9.(GmM)/R`
    B
    `(2sqrt2)/3.(GMm)/R^2`
    C
    `1/(3sqrt8).(GMm)/R^2`
    D
    `sqrt8/(27).(GmM)/R^2`

  • The force of attraction between two bodies of masses 100 kg and 1000 Kg separated by a distance of 10 m is

    A
    `6.67xx10^(-7)N`
    B
    `6.67xx10^(-8)N`
    C
    `6.67xx10^(-9)N`
    D
    `6.67xx10^(-10)`

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    A point mass m is released from rest at a distance of 3R from the centre of a thin-walled hollow sphere of radius R and mass M as shown. The hollow sphere is fixed in position and the only force on the point mass is the gravitational attraction of the hollow sphere. There is a very small hole in the hollow sphere through which the point mass falls as shown. The velocity of a point mass when it passes through point P at a distance R//2 from the centre of the sphere is

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