In a spherical mirror height of an object is 100 cm and height an image is 25 cm and their orientations are same then

Options

A. real image, convex mirror
B. real image concave mirror
C. virtual image , concave mirror
D. virtual image , convex mirror

Answer

To solve the problem, we need to analyze the given information about the spherical mirror and the characteristics of the image formed.

### Step-by-Step Solution:

1. **Identify the Given Data:**
- Height of the object (h_o) = 100 cm
- Height of the image (h_i) = 25 cm
- Orientation of the object and image is the same (both are upright).

2. **Determine the Magnification:**
- Magnification (m) is given by the formula:
\[ m = \frac{h_i}{h_o} \]
- Substituting the values:
\[ m = \frac{25 \text{ cm}}{100 \text{ cm}} = 0.25 \]

3. **Analyze the Magnification:**
- Since the magnification is positive (0.25), it indicates that the image is upright.
- The fact that the magnification is less than 1 (0.25) indicates that the image is diminished.

4. **Determine the Type of Image:**
- Since the image is upright and diminished, it must be a virtual image.
- Virtual images are typically formed by convex mirrors or concave mirrors when the object is located between the focal point and the mirror.

5. **Identify the Type of Mirror:**
- A convex mirror always produces virtual, upright, and diminished images regardless of the position of the object.
- A concave mirror can produce a virtual image if the object is placed between the focal point and the mirror, but it can also produce real images depending on the object's position.

6. **Conclusion:**
- Given that the image is virtual and diminished, the most likely type of mirror that meets these conditions is a **convex mirror**.

### Final Answer:
The image formed is a virtual image, and the type of mirror is a **convex mirror**.

---