If vernier calliper has positive error of 0.2mm. If zero of vernier scale lies between 8.5cm and 8.6cm. If 6th division of vernier scale coincides with main scale. Then reading will be (LC = 0.1MM)

Options

A. 8.56 CM
B. 8.54 CM
C. 8.58 CM
D. 8.60 CM

Answer

To solve the problem step by step, we can follow the reasoning outlined in the video transcript.

### Step 1: Understand the Given Information
- Positive error of the Vernier caliper = 0.2 mm
- The zero of the Vernier scale lies between 8.5 cm and 8.6 cm.
- The 6th division of the Vernier scale coincides with the main scale.
- Least count (LC) of the Vernier caliper = 0.1 mm

### Step 2: Determine the Main Scale Reading (MSR)
The zero of the Vernier scale is between 8.5 cm and 8.6 cm. Therefore, we can take the main scale reading (MSR) as:
\[ \text{MSR} = 8.5 \text{ cm} \]

### Step 3: Determine the Vernier Scale Reading (VSR)
The 6th division of the Vernier scale coincides with the main scale. To find the Vernier scale reading, we multiply the division number by the least count:
\[ \text{VSR} = 6 \times \text{LC} = 6 \times 0.1 \text{ mm} = 0.6 \text{ mm} \]

### Step 4: Convert the Vernier Scale Reading to Centimeters
Since the main scale reading is in centimeters, we should convert the Vernier scale reading from millimeters to centimeters:
\[ \text{VSR in cm} = 0.6 \text{ mm} = \frac{0.6}{10} \text{ cm} = 0.06 \text{ cm} \]

### Step 5: Calculate the Total Reading Before Error Adjustment
Now, we can calculate the total reading before adjusting for the positive error:
\[ \text{Total Reading} = \text{MSR} + \text{VSR in cm} = 8.5 \text{ cm} + 0.06 \text{ cm} = 8.56 \text{ cm} \]

### Step 6: Adjust for the Positive Error
Since there is a positive error of 0.2 mm (which is 0.02 cm), we need to subtract this from the total reading:
\[ \text{Final Reading} = 8.56 \text{ cm} - 0.02 \text{ cm} = 8.54 \text{ cm} \]

### Conclusion
Thus, the final reading of the Vernier caliper is:
\[ \text{Final Reading} = 8.54 \text{ cm} \]