If `tantheta=x` then show that `sin2theta +tan2theta=(4x)/(1-x^(4))`

If tantheta+tan2theta+tantheta. tan2theta=1 then theta =

sec^(4) theta (1-sin^4 theta ) - tan^(2) theta =

If acos2theta+bsin2theta=c" has "theta_(1),theta_(2) as its solutions then show that tantheta_(1)+tantheta_(2)=(2b)/(c+a)tantheta_(1).tantheta_(2)=(c-a)/(c+a) and hence show that tan(theta_(1)+theta_(2))=b//a .

(2 sin theta * tan theta (1- tan theta ) + 2 sin theta sec^(2) theta )/( (1+ tan theta)^(2))=

If tan theta_(1), tan theta_(2) tan theta_(3) and tan theta_(4) are the roots of the equation x^(4) - x^(3) sin 2 beta + x^(2) cos 2 beta - x cos beta - sin beta = "0 then tan" (theta_(1) + theta_(2) + theta_(3) + theta_(4)) is equal to

If 8sin theta cos theta cos2theta cos4theta=sinx then x=

If x=a(sec theta + tan theta)^(2) and y=b(sec theta- tan theta)^(4) , then x^(4)y^(2)=

Show that (1 - sin theta)(1 + sin theta) (1 + tan^2 theta) =1