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In a SHM with time period 2s. Time taken...

In a SHM with time period 2s. Time taken for displacement x to reach `A/2` from mean position is `1/a` find `a`?

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To solve the problem, we need to find the value of \( a \) given that a particle in simple harmonic motion (SHM) has a time period of 2 seconds and takes \( \frac{1}{a} \) seconds to reach a displacement of \( \frac{A}{2} \) from the mean position. ### Step-by-Step Solution: 1. **Identify the Time Period and Calculate Angular Frequency**: The time period \( T \) is given as 2 seconds. The angular frequency \( \omega \) can be calculated using the formula: \[ \omega = \frac{2\pi}{T} \] Substituting \( T = 2 \): \[ \omega = \frac{2\pi}{2} = \pi \, \text{rad/s} \] **Hint**: Remember that angular frequency is related to the time period by this formula. 2. **Set Up the Displacement Equation**: The displacement \( x \) in SHM can be expressed as: \[ x = A \sin(\omega t) \] We need to find the time \( t \) when \( x = \frac{A}{2} \). **Hint**: The sine function relates the displacement to time in SHM. 3. **Substitute the Displacement**: Set \( x = \frac{A}{2} \): \[ \frac{A}{2} = A \sin(\omega t) \] Dividing both sides by \( A \) (assuming \( A \neq 0 \)): \[ \frac{1}{2} = \sin(\omega t) \] **Hint**: Simplifying the equation helps isolate the sine function. 4. **Find the Angle**: From the equation \( \sin(\omega t) = \frac{1}{2} \), we know that: \[ \omega t = \sin^{-1}\left(\frac{1}{2}\right) \] The angle whose sine is \( \frac{1}{2} \) is \( \frac{\pi}{6} \) radians. **Hint**: Recall the values of sine for standard angles. 5. **Solve for Time \( t \)**: Substitute \( \omega = \pi \): \[ \pi t = \frac{\pi}{6} \] Dividing both sides by \( \pi \): \[ t = \frac{1}{6} \, \text{seconds} \] **Hint**: Isolate \( t \) to find the time taken to reach the specified displacement. 6. **Relate Time to \( a \)**: According to the problem, the time taken to reach \( \frac{A}{2} \) is given as \( \frac{1}{a} \): \[ \frac{1}{a} = \frac{1}{6} \] Therefore, we can equate and solve for \( a \): \[ a = 6 \] **Hint**: Equating the two expressions for time allows you to find \( a \). ### Final Answer: The value of \( a \) is \( 6 \).
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