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The number of 2x2 matrices X satisfying ...

The number of `2x2` matrices `X` satisfying the matrix equation `X^2=I(Ii s2x2u n i tm a t r i x)` is 1 (b) 2 (c) 3 (d) infinite

A

0

B

1

C

2

D

more then 3

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To solve the problem, we need to find the number of \(2 \times 2\) matrices \(X\) that satisfy the equation \(X^2 = I\), where \(I\) is the \(2 \times 2\) identity matrix. ### Step-by-Step Solution: 1. **Understanding the Equation**: The equation \(X^2 = I\) implies that multiplying the matrix \(X\) by itself gives the identity matrix. This means that \(X\) is its own inverse, i.e., \(X = X^{-1}\). **Hint**: Recall that the identity matrix \(I\) has the property that \(I \cdot A = A \cdot I = A\) for any matrix \(A\). 2. **Multiplying by \(X^{-1}\)**: If we multiply both sides of the equation \(X^2 = I\) by \(X^{-1}\) (the inverse of \(X\)), we get: \[ X \cdot X = I \implies X = X^{-1} \] **Hint**: Remember that multiplying both sides of an equation by the same non-zero matrix does not change the equality. 3. **Characterizing Matrices**: The condition \(X = X^{-1}\) means that \(X\) is an involutory matrix. In \(2 \times 2\) matrices, this can be satisfied by matrices that have eigenvalues of either \(1\) or \(-1\). **Hint**: Consider the properties of eigenvalues and how they relate to the matrix being its own inverse. 4. **Finding Possible Matrices**: A general form of a \(2 \times 2\) matrix is: \[ X = \begin{pmatrix} a & b \\ c & d \end{pmatrix} \] For \(X\) to satisfy \(X^2 = I\), we can derive conditions on the entries \(a\), \(b\), \(c\), and \(d\). The characteristic polynomial of \(X\) must be \(\lambda^2 - 1 = 0\), leading to eigenvalues of \(1\) and \(-1\). **Hint**: Think about the implications of the eigenvalues on the structure of the matrix. 5. **Constructing Examples**: Some specific examples of \(2 \times 2\) matrices that satisfy \(X^2 = I\) include: - The identity matrix \(I = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix}\) - The matrix \(X_1 = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}\) - The matrix \(X_2 = \begin{pmatrix} -1 & 0 \\ 0 & 1 \end{pmatrix}\) - The matrix \(X_3 = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}\) **Hint**: Try to find other matrices that can be represented in a similar form. 6. **Conclusion**: Since there are infinitely many matrices that can be constructed to satisfy the condition \(X = X^{-1}\) (for example, any rotation or reflection matrix), we conclude that there are infinitely many \(2 \times 2\) matrices \(X\) such that \(X^2 = I\). **Final Answer**: The number of \(2 \times 2\) matrices \(X\) satisfying \(X^2 = I\) is (d) infinite.

To solve the problem, we need to find the number of \(2 \times 2\) matrices \(X\) that satisfy the equation \(X^2 = I\), where \(I\) is the \(2 \times 2\) identity matrix. ### Step-by-Step Solution: 1. **Understanding the Equation**: The equation \(X^2 = I\) implies that multiplying the matrix \(X\) by itself gives the identity matrix. This means that \(X\) is its own inverse, i.e., \(X = X^{-1}\). **Hint**: Recall that the identity matrix \(I\) has the property that \(I \cdot A = A \cdot I = A\) for any matrix \(A\). ...
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