The velocity-time graph of a particle moving in a staight line is shown in the . Find the displacement and the distance trav elled by the particle in `6 s`.
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Answer

`8 m`; `16 m`

Explanation

We know that desplacement is area under `v-t` graph . Area from `0` to `2 s` is `4xx 2=8 m`, area form `2` to `4 s` is `-2 xx2 =-4 m`, area from `4` to `6` s `2xx 2=4 m`
So displacement=`8-4+4=8 m`
When we find distance, we consider all areas to be positive.
So distance=`8+4+4=16 m`.