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A block of mass 2 kg rest on a plane inc...

A block of mass 2 kg rest on a plane inclined al an angle pf `30^(@)` with the horizontal. The coefficient of friction between the block and the surface is 0.7. what will be the frictional force acting on the block?

A

`9.8 N`

B

`0.7 xx 9.8 xx (sqrt(3))N`

C

`9.8 xx (sqrt(3))N`

D

`0.7 xx 9.8N`

Text Solution

Verified by Experts

The correct Answer is:
a
Since `mu mg cos theta gt mg sin theta`
force of friction is `f = mg sin theta`
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