Home
Class 11
PHYSICS
When a bicycle is in motion, the force o...

When a bicycle is in motion, the force of friction exerted by the ground on the two wheels is such that it acts

A

In the backward on the front wheel and in the forward on the rear wheel

B

In the forward direction on the front wheel and in the backward on the rear wheel

C

In the backward direction on both and the rear wheel

D

In the forward direction on both the front and the rear wheel

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the direction of the friction force exerted by the ground on the two wheels of a bicycle in motion, we can break down the analysis into clear steps: ### Step-by-Step Solution: 1. **Understand the Forces Acting on the Bicycle:** - When a bicycle is in motion, the rider pedals to move the bicycle forward. The pedaling force is primarily applied to the front wheel. 2. **Analyze the Front Wheel:** - The front wheel experiences a pedaling force that moves it forward. However, due to the motion of the bicycle, there is a relative motion between the front wheel and the ground. - Since the front wheel is trying to move forward faster than the ground beneath it, the friction force exerted by the ground on the front wheel acts in the opposite direction (backward) to oppose this relative motion. 3. **Analyze the Rear Wheel:** - The rear wheel is connected to the pedals through a chain and rotates as the bicycle moves forward. The rear wheel does not require an external force to move forward; it rotates due to the chain's motion. - As the rear wheel rolls forward, it is also in contact with the ground. The friction force here acts in the same direction as the motion of the bicycle (forward) because it helps to propel the bicycle forward. 4. **Conclusion:** - Therefore, the direction of the friction force on the front wheel is backward (opposing the forward motion), while the direction of the friction force on the rear wheel is forward (supporting the motion). ### Final Answer: - The force of friction exerted by the ground on the front wheel acts backward, and on the rear wheel, it acts forward.
To solve the question regarding the direction of the friction force exerted by the ground on the two wheels of a bicycle in motion, we can break down the analysis into clear steps: ### Step-by-Step Solution: 1. **Understand the Forces Acting on the Bicycle:** - When a bicycle is in motion, the rider pedals to move the bicycle forward. The pedaling force is primarily applied to the front wheel. 2. **Analyze the Front Wheel:** ...
Promotional Banner

Topper's Solved these Questions

  • NEWTON'S LAWS OF MOTION 2

    CENGAGE PHYSICS ENGLISH|Exercise Multiple correct answer type|3 Videos

  • NEWTON'S LAWS OF MOTION 2

    CENGAGE PHYSICS ENGLISH|Exercise Assertion -reasoning|2 Videos

  • NEWTON'S LAWS OF MOTION 2

    CENGAGE PHYSICS ENGLISH|Exercise True And False|4 Videos

  • NEWTON'S LAWS OF MOTION 1

    CENGAGE PHYSICS ENGLISH|Exercise Integer|5 Videos

  • PROPERTIES OF SOLIDS AND FLUIDS

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|2 Videos

Similar Questions

Explore conceptually related problems

(A) : When a bicycle is in motion, the force of friction exerted by the ground on the two wheels is always in forward direction. (R ) : The frictional force only when the bodies are in contact.

Find the force of friction acting between both the blocks shown in the figure.

A roller of mass 500kg is attached by a light horizontal chain to a tractor of mass 500kg. Assume the force of friction exerted by the ground to be 1000N. If the system has a forward acceleration of 2ms^(-2) , calculate (i) the total force required for the motion and (ii) the tension in the chain.

A bicycle has pedal rods of length 16 cm connected to sprocketed disc of radius 10 cm . The bicycle wheels are 70 cm in diameter and the chain runs over a gear of radius 4cm . The speed of the cycle is constant and the cyclist applies 100 N for, that is always perpendicular to the pedal rod, as shown in figure. Assume tension in the lower part of chain is negligible. The cyclist is peddling at a constant rate of two revolutions per second. Assume that the force applied by other foot is zero when one foot is exerting 100 N force. Neglect friction within cycle parts and the rolling friction. The net force of the friction on the rear wheel due to the road is:

"When a person walks on a rough surface the frictional force exerted by the surface on the person is opposite to the direction of his motion". Is it true or false ?

Assertion : Angle of repose is equal to angle of limiting friction. Reason : When the body is just at the point of motion, the force of friction in this stage is called as limiting friction.

A spring is compressed between two toy carts to masses m_1 and m_2 . When the toy carts are released, the spring exerts on each toy cart equal and opposite forces for the same small time t. If the coefficients of friction mu between the ground and the toy carts are equal, then the magnitude of displacements of the toy carts are in the ratio

When a person walks on a rough surface, the frictional force exerted by surface on the person is opposite to the direction of his motion. It is the force exerted by the road on the person that causes the motion.

A car weighs 1800 kg . The distance between its front and back axles is 1.8 m . Its centre of gravity is 1.05 m behind the front axle. Determine the force exerted by the level ground on each front wheel and each back wheel.