Which of the following is/are optically active?

Options

A.
B.
C.
D.

Explanation

To determine which of the given compounds are optically active, we need to check for the presence of a plane of symmetry in each structure. A compound is considered optically active if it does not have a plane of symmetry.

### Step-by-Step Solution:

1. **Identify the Compounds**:
We need to analyze the structures of the compounds provided in the options. Let's denote the options as A, B, C, and D.

2. **Analyze Option A**:
- Structure: COOH, H, COOH, H
- Check for Plane of Symmetry:
- If we draw a vertical line through the center of the molecule, we can see that one COOH group and one H atom are mirrored by the other COOH group and H atom.
- Conclusion: There is a plane of symmetry present, hence this compound is **optically inactive**.

3. **Analyze Option B**:
- Structure: (assumed structure based on context)
- Check for Plane of Symmetry:
- Upon drawing the structure, we find that there is no plane that can divide the molecule into two symmetrical halves.
- Conclusion: There is no plane of symmetry, hence this compound is **optically active**.

4. **Analyze Option C**:
- Structure: COOH, H, H, COOH
- Check for Plane of Symmetry:
- Drawing the structure reveals that if we draw a vertical line through the center, one H atom mirrors the other H atom, and one COOH mirrors the other COOH.
- Conclusion: There is a plane of symmetry present, hence this compound is **optically inactive**.

5. **Analyze Option D**:
- Structure: COOH, H, HCOOH
- Check for Plane of Symmetry:
- In this structure, if we draw a vertical line, the H atom does not mirror the COOH group, indicating no symmetry.
- Conclusion: There is no plane of symmetry, hence this compound is **optically active**.

6. **Final Conclusion**:
- The compounds that are optically active are **B and D**.

### Summary of Results:
- **Optically Active Compounds**: B and D
- **Optically Inactive Compounds**: A and C