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If the multiplicative inverse of a compl...

If the multiplicative inverse of a complex number is ` (sqrt2 +5i)/17` ,then the complex number is

A

`(sqrt2 -5i)/17`

B

`(sqrt2 +5i)/29`

C

`17/27 (sqrt2 -5i)`

D

`17/27 (sqrt2 +5i)`

Text Solution

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The correct Answer is:
To find the complex number \( z \) given its multiplicative inverse \( \frac{\sqrt{2} + 5i}{17} \), we can follow these steps: ### Step 1: Understand the relationship between a complex number and its multiplicative inverse The multiplicative inverse of a complex number \( z \) is given by: \[ \frac{1}{z} = \frac{\sqrt{2} + 5i}{17} \] From this relationship, we can express \( z \) as: \[ z = \frac{17}{\sqrt{2} + 5i} \] ### Step 2: Rationalize the denominator To eliminate the imaginary unit \( i \) from the denominator, we multiply the numerator and denominator by the conjugate of the denominator, which is \( \sqrt{2} - 5i \): \[ z = \frac{17(\sqrt{2} - 5i)}{(\sqrt{2} + 5i)(\sqrt{2} - 5i)} \] ### Step 3: Simplify the denominator Using the difference of squares formula \( (a + b)(a - b) = a^2 - b^2 \): \[ (\sqrt{2})^2 - (5i)^2 = 2 - 25(-1) = 2 + 25 = 27 \] ### Step 4: Substitute back into the expression for \( z \) Now substituting back, we have: \[ z = \frac{17(\sqrt{2} - 5i)}{27} \] ### Step 5: Write the final expression for \( z \) Thus, the complex number \( z \) can be expressed as: \[ z = \frac{17\sqrt{2}}{27} - \frac{85i}{27} \] ### Final Answer The complex number \( z \) is: \[ z = \frac{17\sqrt{2}}{27} - \frac{85i}{27} \]
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