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(1+2i)/(1+3i) is equal to...

`(1+2i)/(1+3i)` is equal to

A

`7/10 -i/10`

B

`7/10 +i/10`

C

`7-i`

D

`7/2 + i/2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \((1 + 2i)/(1 + 3i)\), we will eliminate the imaginary unit \(i\) from the denominator by multiplying the numerator and the denominator by the complex conjugate of the denominator. ### Step-by-step Solution: 1. **Identify the complex conjugate of the denominator:** The denominator is \(1 + 3i\). The complex conjugate of this expression is \(1 - 3i\). 2. **Multiply both the numerator and denominator by the complex conjugate:** \[ \frac{1 + 2i}{1 + 3i} \cdot \frac{1 - 3i}{1 - 3i} = \frac{(1 + 2i)(1 - 3i)}{(1 + 3i)(1 - 3i)} \] 3. **Calculate the denominator:** The denominator can be simplified using the formula for the difference of squares: \[ (1 + 3i)(1 - 3i) = 1^2 - (3i)^2 = 1 - 9(-1) = 1 + 9 = 10 \] 4. **Calculate the numerator:** Expand the numerator: \[ (1 + 2i)(1 - 3i) = 1 \cdot 1 + 1 \cdot (-3i) + 2i \cdot 1 + 2i \cdot (-3i) \] Simplifying this gives: \[ = 1 - 3i + 2i - 6i^2 \] Since \(i^2 = -1\), we can substitute: \[ = 1 - 3i + 2i + 6 = 7 - i \] 5. **Combine the results:** Now we can write the expression as: \[ \frac{7 - i}{10} \] 6. **Separate the real and imaginary parts:** This can be expressed as: \[ \frac{7}{10} - \frac{1}{10}i \] ### Final Answer: Thus, \((1 + 2i)/(1 + 3i) = \frac{7}{10} - \frac{1}{10}i\). ---
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