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If the equations ax^2 + bx + c = 0 and x...

If the equations `ax^2 + bx + c = 0 and x^2 + x + 1= 0` has one common root then `a : b : c` is equal to

A

`1:1:1`

B

`1:2:3`

C

`2:3:1`

D

` 3: 2: 1`

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The correct Answer is:
To solve the problem, we need to find the ratio \( a : b : c \) given that the equations \( ax^2 + bx + c = 0 \) and \( x^2 + x + 1 = 0 \) have one common root. ### Step 1: Identify the roots of the second equation The second equation is: \[ x^2 + x + 1 = 0 \] We can find the roots using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 1, b = 1, c = 1 \). The discriminant is: \[ b^2 - 4ac = 1^2 - 4 \cdot 1 \cdot 1 = 1 - 4 = -3 \] Since the discriminant is negative, the roots are complex and can be expressed as: \[ x = \frac{-1 \pm i\sqrt{3}}{2} \] Let the roots be: \[ \alpha = \frac{-1 + i\sqrt{3}}{2}, \quad \beta = \frac{-1 - i\sqrt{3}}{2} \] ### Step 2: Set up the first equation with a common root Let’s assume that one of the roots of the first equation \( ax^2 + bx + c = 0 \) is \( \alpha \). The sum and product of the roots of the first equation can be expressed as follows: - Sum of roots: \( -\frac{b}{a} \) - Product of roots: \( \frac{c}{a} \) ### Step 3: Relate the roots of both equations Since the first equation has one common root \( \alpha \) and the other root can be denoted as \( r \), we have: - For the first equation: - Sum of roots: \( \alpha + r = -\frac{b}{a} \) - Product of roots: \( \alpha r = \frac{c}{a} \) - For the second equation: - The sum of roots is \( \alpha + \beta = -1 \) - The product of roots is \( \alpha \beta = 1 \) ### Step 4: Equate the sums and products From the sum of roots: \[ \alpha + r = -\frac{b}{a} \] Since \( \alpha + \beta = -1 \), we can write: \[ r = -\frac{b}{a} - \alpha \] From the product of roots: \[ \alpha r = \frac{c}{a} \] Substituting \( r \) gives: \[ \alpha \left(-\frac{b}{a} - \alpha\right) = \frac{c}{a} \] ### Step 5: Solve for \( a, b, c \) From the above equations, we can derive relationships between \( a, b, c \): 1. From the sum of roots, we have: \[ -\frac{b}{a} = -1 \implies b = a \] 2. From the product of roots, we have: \[ \alpha r = 1 \implies c = a \] ### Step 6: Find the ratio Thus, we have: \[ a = b = c \] This implies the ratio: \[ a : b : c = 1 : 1 : 1 \] ### Final Answer The ratio \( a : b : c \) is \( 1 : 1 : 1 \).
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AAKASH INSTITUTE ENGLISH-COMPLEX NUMBERS AND QUADRATIC EQUATIONS-Assignment (Section -B) (objective Type Questions ( one option is correct)
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  4. If 1,2,3 are the roots of the equation x^(3) + ax^(2) + bx + c=0 , th...

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  5. Consider that f(x) =ax^(2) + bx +c, D = b^(2)-4ac , then which of the...

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  17. If the sum of the roots of the quadratic equaion ax^2+ bx +c =0 is equ...

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  20. If a,b are real, then the roots of the quadratic equation (a-b)x^(2)-5...

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