In a `triangleABC`, bc=a, a=2, the value of `2DeltaR` is equal to

Answer

To solve the problem step by step, we need to find the value of \(2\Delta R\) for triangle \(ABC\) given that \(BC = a\) and \(a = 2\).

### Step 1: Understand the terms
- \( \Delta \) represents the area of triangle \(ABC\).
- \( R \) is the circumradius of triangle \(ABC\).

### Step 2: Use the formula for the area of a triangle
The area \( \Delta \) of triangle \(ABC\) can be expressed using the formula:
\[ \Delta = \frac{abc}{4R} \]
where \(a\), \(b\), and \(c\) are the lengths of the sides of the triangle, and \(R\) is the circumradius.

### Step 3: Express \(2\Delta R\)
We want to find \(2\Delta R\). We can rewrite this as:
\[ 2\Delta R = 2 \left(\frac{abc}{4R}\right) R = \frac{abc}{2} \]

### Step 4: Substitute the known values
From the problem, we know:
- \(BC = a = 2\)
- Therefore, \(a = 2\).

Assuming that \(b\) and \(c\) are also equal to \(2\) (for simplicity, as no other values are provided), we can substitute:
\[ abc = 2 \cdot 2 \cdot 2 = 8 \]

### Step 5: Calculate \(2\Delta R\)
Now substituting \(abc\) into the equation for \(2\Delta R\):
\[ 2\Delta R = \frac{8}{2} = 4 \]

### Final Answer
Thus, the value of \(2\Delta R\) is \(4\).

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