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O(g) + 2e^(-) to O^(2-)(g) , DeltaH(eg) ...

`O(g) + 2e^(-) to O^(2-)(g) , DeltaH_(eg) = 744.7` kJ/mole . The positive value of `DeltaH_(eg)` is due to :

A

energy is released to add on `1e^(-) " to " O^(-)`

B

energy is required to add on `1e^(-) " to " O^(-)`

C

energy is needed to add on `1e^(-) " to " O`

D

None of the above is correct

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The correct Answer is:
To understand why the positive value of ΔH_(eg) = 744.7 kJ/mole for the reaction O(g) + 2e^(-) → O^(2-)(g), we need to analyze the concept of electron gain enthalpy and the processes involved in adding electrons to an oxygen atom. ### Step-by-Step Solution: 1. **Definition of Electron Gain Enthalpy (ΔH_(eg))**: - Electron gain enthalpy is defined as the amount of energy released or absorbed when an electron is added to a neutral atom in the gas phase to form a negative ion. 2. **First Electron Gain Enthalpy**: - When the first electron is added to a neutral oxygen atom (O), it forms O^(-). This process is exothermic, meaning it releases energy. - The value for the first electron gain enthalpy of oxygen is approximately -41 kJ/mole. This negative value indicates that energy is released during this process. 3. **Second Electron Gain Enthalpy**: - When a second electron is added to the O^(-) ion to form O^(2-), this process is endothermic. This means that energy must be supplied to overcome the repulsion between the negatively charged O^(-) ion and the incoming electron. - The addition of the second electron requires energy input, which is why the second electron gain enthalpy is positive and significantly higher than the first. 4. **Overall Process**: - The overall reaction involves adding two electrons to the neutral oxygen atom. The first electron adds energy release, while the second electron requires energy input. - Therefore, the total energy change (ΔH_(eg)) for the addition of two electrons results in a positive value of 744.7 kJ/mole. 5. **Conclusion**: - The positive value of ΔH_(eg) = 744.7 kJ/mole is primarily due to the energy required to add the second electron to the already negatively charged O^(-) ion, which experiences electron-electron repulsion.

To understand why the positive value of ΔH_(eg) = 744.7 kJ/mole for the reaction O(g) + 2e^(-) → O^(2-)(g), we need to analyze the concept of electron gain enthalpy and the processes involved in adding electrons to an oxygen atom. ### Step-by-Step Solution: 1. **Definition of Electron Gain Enthalpy (ΔH_(eg))**: - Electron gain enthalpy is defined as the amount of energy released or absorbed when an electron is added to a neutral atom in the gas phase to form a negative ion. 2. **First Electron Gain Enthalpy**: ...
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VMC MODULES ENGLISH-CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES -LEVEL -2
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