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Consider the order O^(2-) lt F^(+) lt Na...

Consider the order `O^(2-) lt F^(+) lt Na^(+) lt Mg^(3+)`. Then correct statement(s) is/are :

A

Increasing order of `Z_(eff)`

B

Increasing order of size

C

Increasing order of I.E.

D

Increasing order of E.A.

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The correct Answer is:
To analyze the order \( O^{2-} < F^{+} < Na^{+} < Mg^{3+} \) and determine the correct statements, we will consider the effective nuclear charge, ionic sizes, and electron affinities of the ions involved. ### Step-by-Step Solution: 1. **Identify the Ions and Their Electron Configurations:** - \( O^{2-} \): Has gained 2 electrons, total of 10 electrons (same as Ne). - \( F^{+} \): Has lost 1 electron, total of 9 electrons. - \( Na^{+} \): Has lost 1 electron, total of 10 electrons (same as Ne). - \( Mg^{3+} \): Has lost 3 electrons, total of 10 electrons (same as Ne). 2. **Determine the Effective Nuclear Charge (Z_eff):** - The effective nuclear charge increases with the number of protons in the nucleus. - \( O^{2-} \) has 8 protons, \( F^{+} \) has 9 protons, \( Na^{+} \) has 11 protons, and \( Mg^{3+} \) has 12 protons. - The effective nuclear charge affects the size of the ions: more protons lead to a stronger attraction of electrons, resulting in a smaller ionic radius. 3. **Analyze the Ionic Sizes:** - The ionic size decreases with increasing positive charge and increases with increasing negative charge. - Therefore, the order of size based on effective nuclear charge is: - \( O^{2-} > F^{+} > Na^{+} > Mg^{3+} \) - This confirms the order \( O^{2-} < F^{+} < Na^{+} < Mg^{3+} \) in terms of increasing size. 4. **Consider Electron Affinities:** - Electron affinity is the energy change when an electron is added to a neutral atom. - \( O^{2-} \) is less stable than \( F^{+} \) because it has a higher negative charge and is less favorable to gain another electron. - The order of electron affinity (from most favorable to least) is: - \( F > Na > Mg > O \) - This indicates that \( O^{2-} \) has the least favorable electron affinity. 5. **Conclusion:** - The correct order based on size is \( O^{2-} > F^{+} > Na^{+} > Mg^{3+} \). - The order \( O^{2-} < F^{+} < Na^{+} < Mg^{3+} \) is indeed correct in terms of increasing size.

To analyze the order \( O^{2-} < F^{+} < Na^{+} < Mg^{3+} \) and determine the correct statements, we will consider the effective nuclear charge, ionic sizes, and electron affinities of the ions involved. ### Step-by-Step Solution: 1. **Identify the Ions and Their Electron Configurations:** - \( O^{2-} \): Has gained 2 electrons, total of 10 electrons (same as Ne). - \( F^{+} \): Has lost 1 electron, total of 9 electrons. - \( Na^{+} \): Has lost 1 electron, total of 10 electrons (same as Ne). ...
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VMC MODULES ENGLISH-CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES -LEVEL -2
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  16. Which is the correct order of ionization energies?

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